Nuprl Lemma : filter2_functionality 4,23

A:Type, L:A List, f1f2:(||L||). f1 = f2  filter2(f2;L) = filter2(f1;L A List 
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Definitionst  T, x:AB(x), filter2(P;L), Prop, , ||as||, {i..j}, P  Q
Lemmasint seg wf, length wf1, bool wf, filter2 wf

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